The reaction of N,N'-diphenylthiourea with co | vedclass

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(C) The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ under heating conditions is a decomposition reaction.The chemical equation for the

Vedclass · Accepted Answer

$C_6H_5-N=C=S$ and $C_6H_5NH_3^+Cl^-$

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(C) The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ under heating conditions is a decomposition reaction.The chemical equation for the reaction is:$(C_6H_5NH)_2C=S + HCl \xrightarrow{Heat} C_6H_5-N=C=S + C_6H_5NH_3^+Cl^-$Here,$A$ is phenyl isothiocyanate $(C_6H_5-N=C=S)$ and $B$ is aniline hydrochloride $(C_6H_5NH_3^+Cl^-)$.Therefore,the correct option is $C$.

The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ upon heating is given by:
$(C_6H_5NH)_2C=S \xrightarrow{conc. HCl, Heat} A + B$
The unknown compounds $A$ and $B$ in the above reaction are:

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The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ upon heating is given by:$(C_6H_5NH)_2C=S \xrightarrow{conc. HCl, Heat} A + B$The unknown compounds $A$ and $B$ in the above reaction are: